Computing the Hybridization Number of Two Phylogenetic Trees Is Fixed-Parameter Tractable

Reticulation processes in evolution mean that the ancestral history of certain groups of present-day species is non-tree-like. These processes include hybridization, lateral gene transfer, and recombination. Despite the existence of reticulation, such events are relatively rare and, so, a fundamenta...

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Published inIEEE/ACM transactions on computational biology and bioinformatics Vol. 4; no. 3; pp. 458 - 466
Main Authors Bordewich, M., Semple, C.
Format Journal Article
LanguageEnglish
Published United States IEEE 01.07.2007
The Institute of Electrical and Electronics Engineers, Inc. (IEEE)
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ISSN1545-5963
1557-9964
2374-0043
1557-9964
DOI10.1109/tcbb.2007.1019

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Summary:Reticulation processes in evolution mean that the ancestral history of certain groups of present-day species is non-tree-like. These processes include hybridization, lateral gene transfer, and recombination. Despite the existence of reticulation, such events are relatively rare and, so, a fundamental problem for biologists is the following: Given a collection of rooted binary phylogenetic trees on sets of species that correctly represent the tree-like evolution of different parts of their genomes, what is the smallest number of "reticulation" vertices in any network that explains the evolution of the species under consideration? It has been previously shown that this problem is NP-hard even when the collection consists of only two rooted binary phylogenetic trees. However, in this paper, we show that the problem is fixed-parameter tractable in the two-tree instance when parameterized by this smallest number of reticulation vertices.
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ISSN:1545-5963
1557-9964
2374-0043
1557-9964
DOI:10.1109/tcbb.2007.1019