“Spectral implies Tiling” for three intervals revisited

Bose, Anil Kumar, Krishnan and Madan (2010) showed that “Tiling implies Spectral” holds for a union of three intervals and the reverse implication was studied under certain restrictive hypotheses on the associated spectrum. In this paper, we reinvestigate the “Spectral implies Tiling” part of Fugled...

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Published inForum mathematicum Vol. 26; no. 4; pp. 1247 - 1260
Main Authors Bose, Debashish, Madan, Shobha
Format Journal Article
LanguageEnglish
Published Berlin De Gruyter 01.07.2014
Walter de Gruyter GmbH
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ISSN0933-7741
1435-5337
DOI10.1515/forum-2011-0129

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Abstract Bose, Anil Kumar, Krishnan and Madan (2010) showed that “Tiling implies Spectral” holds for a union of three intervals and the reverse implication was studied under certain restrictive hypotheses on the associated spectrum. In this paper, we reinvestigate the “Spectral implies Tiling” part of Fuglede's conjecture for the three interval case. We first show that the “Spectral implies Tiling” for two intervals follows from the simple fact that two distinct circles have at most two points of intersections. We then attempt this for the case of three intervals and except for one situation are able to prove “Spectral implies Tiling”. Finally, for the exceptional case, we show a connection to a problem of generalized Vandermonde varieties.
AbstractList Bose, Anil Kumar, Krishnan and Madan (2010) showed that “Tiling implies Spectral” holds for a union of three intervals and the reverse implication was studied under certain restrictive hypotheses on the associated spectrum. In this paper, we reinvestigate the “Spectral implies Tiling” part of Fuglede's conjecture for the three interval case. We first show that the “Spectral implies Tiling” for two intervals follows from the simple fact that two distinct circles have at most two points of intersections. We then attempt this for the case of three intervals and except for one situation are able to prove “Spectral implies Tiling”. Finally, for the exceptional case, we show a connection to a problem of generalized Vandermonde varieties.
Bose, Anil Kumar, Krishnan and Madan (2010) showed that "Tiling implies Spectral" holds for a union of three intervals and the reverse implication was studied under certain restrictive hypotheses on the associated spectrum. In this paper, we reinvestigate the "Spectral implies Tiling" part of Fuglede's conjecture for the three interval case. We first show that the "Spectral implies Tiling" for two intervals follows from the simple fact that two distinct circles have at most two points of intersections. We then attempt this for the case of three intervals and except for one situation are able to prove "Spectral implies Tiling". Finally, for the exceptional case, we show a connection to a problem of generalized Vandermonde varieties. [PUBLICATION ABSTRACT]
Author Madan, Shobha
Bose, Debashish
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Snippet Bose, Anil Kumar, Krishnan and Madan (2010) showed that “Tiling implies Spectral” holds for a union of three intervals and the reverse implication was studied...
Bose, Anil Kumar, Krishnan and Madan (2010) showed that "Tiling implies Spectral" holds for a union of three intervals and the reverse implication was studied...
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SubjectTerms 42A99
Fuglede's conjecture
Spectral sets
spectrum
tiling
Title “Spectral implies Tiling” for three intervals revisited
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Volume 26
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