How to Cut Corners and Get Bounded Convex Curvature
We describe an algorithm for solving an important geometric problem arising in computer-aided manufacturing. When cutting away a region from a solid piece of material—such as steel, wood, ceramics, or plastic—using a rough tool in a milling machine, sharp convex corners of the region cannot be done...
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          | Published in | Discrete & computational geometry Vol. 69; no. 4; pp. 1195 - 1231 | 
|---|---|
| Main Authors | , | 
| Format | Journal Article | 
| Language | English | 
| Published | 
        New York
          Springer US
    
        01.06.2023
     Springer Nature B.V  | 
| Subjects | |
| Online Access | Get full text | 
| ISSN | 0179-5376 1432-0444  | 
| DOI | 10.1007/s00454-022-00404-w | 
Cover
| Summary: | We describe an algorithm for solving an important geometric problem arising in computer-aided manufacturing. When cutting away a region from a solid piece of material—such as steel, wood, ceramics, or plastic—using a rough tool in a milling machine, sharp convex corners of the region cannot be done properly, but have to be left for finer tools that are more expensive to use. We want to determine a toolpath that maximizes the use of the rough tool. In order to formulate the problem in mathematical terms, we introduce the notion of bounded convex curvature. A region of points in the plane
Q
has
bounded convex curvature
if for any point
x
∈
∂
Q
, there is a unit disk
U
and
ε
>
0
such that
x
∈
∂
U
and all points in
U
within distance
ε
from
x
are in 
Q
. This translates to saying that as we traverse the boundary
∂
Q
with the interior of
Q
on the left side, then
∂
Q
turns to the left with curvature at most 1. There is no bound on the curvature where
∂
Q
turns to the right. Given a region of points
P
in the plane, we are now interested in computing the maximum subset
Q
⊆
P
of bounded convex curvature. The difference in the requirement to left- and right-curvature is a natural consequence of different conditions when machining convex and concave areas of 
Q
. We devise an algorithm to compute the unique maximum such set
Q
, when the boundary of
P
consists of
n
line segments and circular arcs of arbitrary radii. In the general case where
P
may have holes, the algorithm runs in time
O
(
n
2
)
and uses
O
(
n
) space. If
P
is simply-connected, we describe a faster
O
(
n
log
n
)
time algorithm. | 
|---|---|
| Bibliography: | ObjectType-Article-1 SourceType-Scholarly Journals-1 ObjectType-Feature-2 content type line 14  | 
| ISSN: | 0179-5376 1432-0444  | 
| DOI: | 10.1007/s00454-022-00404-w |